JEE Main 2021 Physics question
A free electron of 2.6 eV energy collides with a ion. This results in the formation of a hydrogen atom in the first excited state and a photon is released. Find the frequency of the emitted photon. (h = Js)
Answer: (C)
A free electron of 2.6 eV energy collides with a ion. This results in the formation of a hydrogen atom in the first excited state and a photon is released. Find the frequency of the emitted photon. (h = Js)