The value of _ x 1 2 ( 8x - 3 2x - 1 - 4x^2 + 1 4x^2 - 1 ) is

MHT CET Mathematics question

The value of is

Answer: (D)

With common denominator the numerator is (4x^212x^2$ + 2x - 4 = 2(3x + 2)(2x -

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Question ID VK-027953