JEE Main 2022 Mathematics question
Let dy/dx = (ax − by + a)/(bx + cy + a), where a, b, c are constants, represent a circle passing through the point (2, 5). Then the shortest distance of the point (11, 6) from this circle is
Answer: (2)
Solution
(bx + cy + a)dy = (ax − by + a)dx gives b d(xy) + cy dy + a dy − ax dx − a dx = 0. Integrating, bxy + + ay − − ax = k. For a circle b = 0 and c = −a, so . Through (2, 5): $4 + 25 + 4 - 10 =
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