MHT CET Physics question
Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity . The boy at A starts running simultaneously with velocity v and catches the other boy in a time where t is
Answer: (B)
Solution
To meet, A's velocity component perpendicular to AB must equal and the component along AB is , so $t =
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