MHT CET Physics question
The M.I. of a circular ring of radius R and mass M about a tangent perpendicular to its plane is
Answer: (D)
Solution
I=I_{cm}+MR^2=MR^2+MR^2=2MR^2 by the parallel axes theorem. Hence the correct option is (d).
The M.I. of a circular ring of radius R and mass M about a tangent perpendicular to its plane is
I=I_{cm}+MR^2=MR^2+MR^2=2MR^2 by the parallel axes theorem. Hence the correct option is (d).