MHT CET Physics question
A body of mass m slides down on an inclined plane and reaches the bottom with a velocity 'v'. If the same mass were in the form of a ring which rolls down on the inclined plane, then the velocity of the ring at the bottom will be
Answer: (B)
Solution
Sliding gives ; for the ring mgh=\frac{1}{2}mv'^2+\frac{1}{2}(mR^2)\frac{v'^2}{R^2}=mv'^2, so and
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