MHT CET Physics question
The moment of inertia of a solid sphere of mass M and radius R about its diameter is . Its M.I. about parallel axis passing through a point at a distance (R/2) from its centre is
Answer: (C)
Solution
I=\frac{2}{5}MR^2+M\left(\frac{R}{2}\right)^2=\frac{8}{20}MR^2+\frac{5}{20}MR^2=\frac{13}{20}MR^2;
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