MHT CET Physics question
Moment of inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is . If the same rod is bent into a ring and its moment of inertia about its diameter is , then the ratio is
Answer: (A)
Solution
Rod: I = mL²/12. Ring of circumference L has R = L/2pi and I' = mR²/2 = mL²/(8pi²); I/I' =
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