MHT CET Physics question
A thin circular ring of mass and radius is rotating about its axis with a constant angular velocity . Two objects each of mass are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with an angular velocity equal to
Answer: (D)
Solution
Angular momentum is conserved: mR² ω = (m + 2M)R² ω', so ω' = m ω/(m + 2M). (a) is larger than ω (impossible
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