MHT CET Physics question
A ring of mass and radius is rotating about its axis with angular velocity . Two identical bodies each of mass are now gently attached at the two ends of a diameter of the ring. Because of this, the kinetic energy loss will be
Answer: (B)
Solution
Conservation of angular momentum: ω' = M ω/(M + 2m); loss = (1/2)MR² ω² - (1/2)(M + 2m)R² ω'² = (1/2)MR² ω²
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