MHT CET Physics question
When a 12000 J of work is done on a flywheel, its frequency of rotation increases from 10 Hz to 20 Hz. The moment of inertia of flywheel about its axis of rotation is (Take ) [MHTCET 2019]
Answer: (B)
Solution
Work = change in KE = (1/2)I(2pi)²(20² - 10²) = 600 pi² I = 12000, so I = 20/pi² = 2 kg m²
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account