MHT CET Physics question
A mass is whirled in a circular path with constant angular velocity and its linear velocity is . If the string is now halved keeping the angular momentum same, the linear velocity is [MHTCET 2019]
Answer: (A)
Solution
Angular momentum L = mvr is constant, so halving r doubles v: 2v; v/2, v and v √2 contradict L = mvr. Hence the correct option is (a).