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MHT CET Physics question

PhysicsSystems of Particles and Rotational MotionMHT CET

The moment of inertia of a ring about an axis passing through the centre and perpendicular to its plane is . It is rotating with angular velocity . Another identical ring is gently placed on it, so that their centres coincide. If both the rings are rotating about the same axis, then loss in kinetic energy is [MHTCET 2018]

Answer: (B)

Solution

Angular momentum conservation gives ω' = ω/2; loss = (1/2)I ω² - (1/2)(2I)(ω/2)² =

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Question ID VK-040790