MHT CET Physics question
A solid cylinder of radius 'R' and mass 'M' rolls down an inclined plane of height 'h'. When it reaches the bottom of the plane, its rotational kinetic energy is (g = acceleration due to gravity) [MHT-CET 2021, MHT-CET 2021]
Answer: (C)
Solution
Rolling: Mgh=\frac12Mv^2+\frac14Mv^2=\frac34Mv^2; rotational KE
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account