MHT CET Physics question
A solid cylinder of mass 'M' and radius 'R' rolls down a smooth inclined plane about its own axis and reaches the bottom with velocity 'v'. The height of the inclined plane is (g = acceleration due to gravity) [MHT-CET 2021, MHT-CET 2021]
Answer: (D)
Solution
Mgh=\frac12Mv^2+\frac12\cdot\frac12MR^2\frac{v^2}{R^2}=\frac34Mv^2, so
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