If the density of methanol is 0.8 kg L^ -1 , what is its volume needed for making 4 L of its 0.25M solution?

MHT CET Chemistry question

If the density of methanol is 0.8 kg , what is its volume needed for making 4 L of its 0.25M solution?

Answer: (C)

Moles of CH₃OH = 4 × 0.25 = 1 mol = 32 g; volume = 32 g / 800 g L⁻¹ = 0.04

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Question ID VK-041126