MHT CET Chemistry question
Rearrange the following (I to IV) in the order of increasing masses and choose the correct answer (atomic mass; O = 16, Cu = 63, N = 14) I. 1 molecule of oxygen. II. 1 atom of nitrogen. III. g molecular weight of oxygen. IV. g atomic weight of copper.
Answer: (A)
Solution
Masses: I = 32/6.022×10²³ = 5.3×10⁻²³ g, II = 14/6.022×10²³ = 2.3×10⁻²³ g, III = 10⁻¹⁰ × 32 = 3.2×10⁻⁹ g, IV = 10⁻¹⁰ × 63 = 6.3×10⁻⁹
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