MHT CET Chemistry question
molecules are removed from 200 mg of . The moles of left are
Answer: (A)
Solution
Initial moles = 0.200/44 = 4.55 × 10⁻³; removed = 10²¹/6.022×10²³ = 1.66 × 10⁻³; left = 2.88 × 10⁻³
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