MHT CET Chemistry question
A metal oxide has the formula . It can be reduced by hydrogen to give free metal and water. 0.1596 g of this metal oxide requires 6 mg of hydrogen for complete reduction. What is the atomic weight of metal?
Answer: (C)
Solution
6 mg H₂ is 0.006 equivalent of oxide, so equivalent weight of oxide = 0.1596/0.006 = 26.6 and of metal = 26.6 −
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