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MHT CET Chemistry question

ChemistrySome Basic Concepts of ChemistryMHT CET

The number of ions present in 222 g anhydrous is

Answer: (D)

Solution

222 g CaCl₂ = 2 mol, giving 4 mol Cl⁻ = 4 × 6.023 × 10²³ = 2.409 × 10²⁴

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Question ID VK-041160