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MHT CET Chemistry question

ChemistrySome Basic Concepts of ChemistryMHT CET

A sample of a mixture of and weighing 4.22 g was treated to precipitate all the as . This is then heated and quantitatively converted into 0.959 g of . Calculate the percentage of in the mixture. (Atomic mass of , , and )

Answer: (C)

Solution

0.959 g CaO = 0.959/56 = 0.01713 mol Ca, so CaCl₂ = 0.01713 × 111 = 1.901 g and % = 1.901/4.22 ×

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Question ID VK-041175