MHT CET Chemistry question
0.5 g of fuming (oleum) is diluted with water. This solution is completely neutralized by 26.7 mL of 0.4 NaOH. The percentage of free in the sample is:
Answer: (C)
Solution
Let x g be free SO₃ (E = 40) and (0.5 − x) g H₂SO₄ (E = 49): x/40 + (0.5 − x)/49 = 26.7 × 0.4/1000 = 0.01068,
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account