MHT CET Chemistry question

ChemistryRedox ReactionsMHT CET

0.5 g of fuming (oleum) is diluted with water. This solution is completely neutralized by 26.7 mL of 0.4 NaOH. The percentage of free in the sample is:

Answer: (C)

Solution

Let x g be free SO₃ (E = 40) and (0.5 − x) g H₂SO₄ (E = 49): x/40 + (0.5 − x)/49 = 26.7 × 0.4/1000 = 0.01068,

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Question ID VK-041202