MHT CET Chemistry question
0.52 g of dibasic acid required 100 mL of 0.1 NaOH for complete neutralization. The equivalent weight of acid is:
Answer: (B)
Solution
Equivalents of NaOH = 0.1 × 0.1 = 0.01 = equivalents of acid, so equivalent weight = 0.52/0.01 = 52; 26, 104 and
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