MHT CET Chemistry question

1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is

Answer: (D)

Solution

Equivalent weight of hydroxide = E + 17 and of oxide = E + 8, so 1.520/(E + 17) = 0.995/(E + 8), giving E = 9.06 ≈

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Question ID VK-041218