If 250 mL of a solution contains 2.7 g of H_3PO_4 , the normality of the solution is:

MHT CET Chemistry question

If 250 mL of a solution contains 2.7 g of , the normality of the solution is:

Answer: (B)

Moles = 2.7/98 = 0.0276 mol, so M = 0.0276/0.25 = 0.11 M and N = 3 × 0.11 = 0.33 N (n-factor 3 for

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Question ID VK-041225