Vapour density of a volatile substance is 4 ( CH_4 = 1). Its molecular weight would be:

MHT CET Chemistry question

Vapour density of a volatile substance is 4 ( = 1). Its molecular weight would be:

Answer: (C)

With CH₄ (M = 16) as the reference, M = 4 × 16 = 64; 8 would result only from H₂ as reference,

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Question ID VK-041226