MHT CET Chemistry question

Volume of 0.1 NaOH needed for the neutralisation of 20 mL of 0.05 oxalic acid is:

Answer: (C)

Solution

Oxalic acid is dibasic so its meq = 20 × 0.05 × 2 = 2 meq, and V × 0.1 = 2 gives V = 20 mL; 10 mL results if oxalic acid

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Question ID VK-041257