MHT CET Chemistry question

The mole fraction of NaCl in a solution containing 1 mole of NaCl in 1000 g of water is :

Answer: (A)

Solution

n(water) = 1000/18 = 55.5 mol so x(NaCl) = 1/(1 + 55.5) = 0.0177; 0.5 would need equal

Create a free account to read the complete working, and practise questions like this in a timed test.

Question ID VK-041267