MHT CET Chemistry question
5.85 g of NaCl are dissolved in 90 g of water. The mole fraction of NaCl is:
Answer: (D)
Solution
n(NaCl) = 0.1 mol and n(H₂O) = 90/18 = 5 mol, so x = 0.1/5.1 = 0.0196; 0.1 is the
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