MHT CET Chemistry question
171 g of cane sugar (mol. wt. = 342) are dissolved in 1000 g of water at 30°C. If the density of solution is 1.1 g/mL, then:
Answer: (A)
Solution
n = 0.5 mol; molality = 0.5/1 kg = 0.5 m, while volume of solution = 1171/1.1 = 1064.5 mL so molarity = 0.5/1.0645 =
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