MHT CET Chemistry question

What weight of sodium hydroxide is required to neutralize 100 mL of 0.1 HCl?

Answer: (C)

Solution

100 mL × 0.1 N = 10 meq = 0.01 eq of NaOH = 0.01 × 40 = 0.4 g; 4.0 g, 0.04

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Question ID VK-041303