Total number of atoms present in 1.0 cm^3 of solid glucose (density 0.8 g/cm^3) at 25°C are:

MHT CET Chemistry question

Total number of atoms present in 1.0 cm of solid glucose (density 0.8 g/cm) at 25°C are:

Answer: (B)

Mass = 0.8 g = 0.8/180 = 4.44 × 10⁻³ mol of C₆H₁₂O₆ with 24 atoms per molecule, so atoms = 4.44 × 10⁻³ × 24 × 6.02 × 10²³ =

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Question ID VK-041320