MHT CET Chemistry question
The vapour density of a volatile chloride of a metal is 95 and the specific heat of the metal is 0.13 cal/g. The equivalent weight of the metal will be:
Answer: (B)
Solution
Approximate atomic weight = 6.4/0.13 ≈ 49.2 and M(chloride) = 2 × 95 = 190, so valency = (190 − 49.2)/35.5 ≈ 4 and the equivalent weight = 49.2/4
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