MHT CET Chemistry question
What weight of silver chloride will be precipitated when a solution containing 4.77 g of is added to a solution of 5.77 g of ? (Na = 23, Cl = 35.5, Ag = 108, = 14 and = 16)
Answer: (B)
Solution
n(NaCl) = 4.77/58.5 = 0.0815 mol and n(AgNO₃) = 5.77/170 = 0.0339 mol, so AgNO₃ is limiting and AgCl = 0.0339 × 143.5 = 4.87 g;
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