MHT CET Chemistry question

Not in JEE Main or NEET syllabus

Xenon crystallizes in face centre cubic lattice and the edge of the unit cell is 620 pm, then the radius of Xenon atom is

Answer: (A)

Solution

In fcc the atoms touch along the face diagonal, so 4r = √2a and r = 620 × 1.414/4 = 219.2 pm; 438.5 pm is

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Question ID VK-042968