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MHT CET Chemistry question

ChemistryThe Solid StateMHT CET

Not in JEE Main or NEET syllabus

crystallises in bcc lattice with edge length of unit cell equal to 387 pm. If radius of is 181 pm, the radius of will be

Answer: (B)

Solution

In bcc-type CsCl structure the body diagonal gives √3a = 2(r+ + r-), so r+ + r- = 1.732 × 387/2 = 335.1

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Question ID VK-042976