MHT CET Chemistry question
Not in JEE Main or NEET syllabus
The edge length of the unit cell of NaCl crystal lattice is 552 pm. If ionic radius of sodium ion is 95 pm, what is the ionic radius of chloride ion?
Answer: (C)
Solution
In NaCl a = 2(r+ + r-), so r- = 552/2 - 95 = 181 pm; 190 pm, 368 pm and 276 pm
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