MHT CET Chemistry question

Not in JEE Main or NEET syllabus

Xenon crystallises in the fcc lattice and the edge of the unit cell is 620pm. The nearest neighbouring distance of Xe is

Answer: (A)

Solution

In fcc the nearest neighbours touch along the face diagonal, so the distance \dfrac{a}{\sqrt{2}}\dfrac{620}{1.414}$ ≈

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Question ID VK-043166