MHT CET Chemistry question
Not in JEE Main or NEET syllabus
Iron crystallises in a bcc system with a lattice parameter of 2.861 A. Calculate the density of iron in the bcc system (atomic weight of Fe = 56, mol)
Answer: (A)
Solution
\dfrac{ZM}{N_A a^3}\dfrac{2 × 56}{6.02×10^{23}×(2.861×10^{-8})^3}$ = 7.94\
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account