MHT CET Chemistry question

Haloalkane in the presence of alcoholic KOH undergoes [MP PMT 1996, KCET (Engg/Med.) 2002]

Answer: (A)

Solution

Alcoholic KOH is a strong base in a non-aqueous medium, so it removes HX (β-elimination) to give an alkene;

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Question ID VK-043721