MHT CET Physics question
Length of conductor is double and its radius is halved its resistance is :
Answer: (D)
Solution
R = ρl/(πr²) ∝ l/r², so R′ = 2/(1/2)² = 8 times the original value. Hence the correct option is (d).
Length of conductor is double and its radius is halved its resistance is :
R = ρl/(πr²) ∝ l/r², so R′ = 2/(1/2)² = 8 times the original value. Hence the correct option is (d).