MHT CET Physics question
With resistances P and Q in the left and the right gap respectively of a metre 3 : 4. When P and Q are increased by each, the null point divides the wire in the ratio 5 : 6. The values of P and Q are
Answer: (A)
Solution
P/Q = 3/4 and (P + 20)/(Q + 20) = 5/6 give 3Q − 4P = 0 and 5Q − 6P = 20, so P =
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