MHT CET Physics question
The mean radius of earth is 6400 km.The acceleration due to gravity at its surface is . The mass of earth is , (G= N m/kg,)
Answer: (C)
Solution
\dfrac{gR^2}{G}\dfrac{9.8×(6.4×10^6)^2}{6.67×10^{-11}}$≈6.0×
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