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MHT CET Physics question

PhysicsGravitationMHT CET

The radius of earth is m, its mean density kg and the gravitational constant is . The gravitational potential of the earth surface is,

Answer: (C)

Solution

\dfrac{GM}{R}\tfracR^2\tfrac10^{-11})(510^3)(610^6)^2$

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Question ID VK-059873