MHT CET Physics question
With what velocity should a satellite be launched from a height of 600 km above the surface of earth so as to move in a circular path ? (G= SI unit , (M= kg , R=6400 km,)
Answer: (B)
Solution
\sqrt{\dfrac{GM}{R+h}}\sqrt{\dfrac{6.67×10^{-11}×5.98×10^{24}}{7×10^{6}}}$≈7.55×1
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