MHT CET Chemistry question
If 0.15g of a solute dissolved in 15g of solvent is boiled at a temperature higher by C than that of the pure solvent. The molecular weight of the substance (molal elevation constant for the solvent is C) is
Answer: (D)
Solution
\dfrac{K_b w_B×1000}{Δ T_b w_A}\dfrac{2.16×0.15×1000}${0.216×
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