Test SeriesFree PYQsExamsPricing

MHT CET Chemistry question

ChemistrySolutionsMHT CET

What will be the molality of a solution having 18 g of glucose (molecular weight = 180) dissolved in 500 g of water? [CBSE PMT 2000]

Answer: (C)

Solution

Moles of glucose = 18/180 = 0.1 mol in 0.5 kg of water, so molality = 0.1/0.5 = 0.2

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-061140