MHT CET Chemistry question

Chemistry Solutions MHT CET

9 g of glucose (mol wt = 180) is dissolved in 90 g of . Relative lowering of vapour pressure is

(A)0.99
(B)0.099
(C)0.0099Correct
(D)0.00099

Answer: (C)

Solution

mol and mol, so $ = =

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Question ID VK-061152