MHT CET Chemistry question

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A solution contains 0.524 g of camphor (molar mass = 152 g/mol dissolved in 36.8 g) of ether (boiling point = 34.6 ℃). The molal elevation constant per 100 g of ether is 19.4 K mol. The boiling point of the solution is

Answer: (B)

Solution

Moles of camphor = 0.524/152 = 0.00345 mol in 36.8 g, i.e. 0.00937 mol per 100 g; K; $ = 307.6

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Question ID VK-061196