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MHT CET Chemistry question

ChemistrySolutionsMHT CET

At 300 K, vapour pressure of substance A is 0.95 atm and vapour pressure of substance B is 0.15 atm. A solution of A and B is prepared and allowed to equilibrate with its vapour. The vapour is found to have equal moles of A and B. What is the mole fraction of A in the original solution?

Answer: (B)

Solution

Equal moles in vapour means : , so $ = 0.15/1.10 =

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Question ID VK-061199